Skip to content
Open
Show file tree
Hide file tree
Changes from all commits
Commits
File filter

Filter by extension

Filter by extension

Conversations
Failed to load comments.
Loading
Jump to
Jump to file
Failed to load files.
Loading
Diff view
Diff view
Binary file not shown.
93 changes: 77 additions & 16 deletions 02_activities/assignments/Cohort_8/assignment1.sql
Original file line number Diff line number Diff line change
Expand Up @@ -4,17 +4,21 @@

--SELECT
/* 1. Write a query that returns everything in the customer table. */


SELECT *
FROM customer;

/* 2. Write a query that displays all of the columns and 10 rows from the cus- tomer table,
sorted by customer_last_name, then customer_first_ name. */


SELECT *
FROM customer
ORDER by customer_last_name, customer_first_name
LIMIT 10;

--WHERE
/* 1. Write a query that returns all customer purchases of product IDs 4 and 9. */

SELECT *
FROM customer_purchases
WHERE product_id IN (4, 9);


/*2. Write a query that returns all customer purchases and a new calculated column 'price' (quantity * cost_to_customer_per_qty),
Expand All @@ -23,10 +27,16 @@ filtered by customer IDs between 8 and 10 (inclusive) using either:
2. one condition using BETWEEN
*/
-- option 1

SELECT * ,
quantity * cost_to_customer_per_qty as price
FROM customer_purchases
WHERE customer_id >7 AND customer_id <10;

-- option 2

SELECT * ,
quantity * cost_to_customer_per_qty as price
FROM customer_purchases
WHERE customer_id BETWEEN 8 and 10;


--CASE
Expand All @@ -35,27 +45,58 @@ Using the product table, write a query that outputs the product_id and product_n
columns and add a column called prod_qty_type_condensed that displays the word “unit”
if the product_qty_type is “unit,” and otherwise displays the word “bulk.” */

SELECT
product_id,
product_name,
CASE
WHEN product_qty_type = 'unit' THEN 'unit'
ELSE 'bulk'
END AS prod_qty_type_condensed
FROM product;


/* 2. We want to flag all of the different types of pepper products that are sold at the market.
add a column to the previous query called pepper_flag that outputs a 1 if the product_name
contains the word “pepper” (regardless of capitalization), and otherwise outputs 0. */

SELECT
product_id,
product_name,
CASE
WHEN product_name LIKE '%pepper%' THEN '1'
ELSE '0'
END AS pepper_flag
FROM product;


--JOIN
/* 1. Write a query that INNER JOINs the vendor table to the vendor_booth_assignments table on the
vendor_id field they both have in common, and sorts the result by vendor_name, then market_date. */



SELECT
v.vendor_name,
v.vendor_id,
v.vendor_type,
vba.booth_number,
vba.market_date

FROM vendor as v
inner JOIN vendor_booth_assignments as vba
WHERE v.vendor_id = vba.vendor_id
ORDER by vendor_name, market_date;

/* SECTION 3 */

-- AGGREGATE
/* 1. Write a query that determines how many times each vendor has rented a booth
at the farmer’s market by counting the vendor booth assignments per vendor_id. */

SELECT
v.vendor_name,
v.vendor_id,
COUNT(*) AS booth_assignments
FROM vendor v
JOIN vendor_booth_assignments vba
ON v.vendor_id = vba.vendor_id
GROUP BY v.vendor_id, v.vendor_name
ORDER BY booth_assignments DESC, v.vendor_name;


/* 2. The Farmer’s Market Customer Appreciation Committee wants to give a bumper
Expand All @@ -64,7 +105,17 @@ of customers for them to give stickers to, sorted by last name, then first name.

HINT: This query requires you to join two tables, use an aggregate function, and use the HAVING keyword. */


SELECT
c.customer_id,
c.customer_last_name,
c.customer_first_name,
round (SUM(cp.quantity * cp.cost_to_customer_per_qty),2) AS total_spent
FROM customer c
JOIN customer_purchases cp
on c.customer_id = cp.customer_id
GROUP by c.customer_id, c.customer_last_name, c.customer_first_name
HAVING sum(cp.quantity * cp.cost_to_customer_per_qty) > 2000
ORDER by c.customer_last_name, c.customer_first_name;

--Temp Table
/* 1. Insert the original vendor table into a temp.new_vendor and then add a 10th vendor:
Expand All @@ -77,8 +128,19 @@ When inserting the new vendor, you need to appropriately align the columns to be
-> To insert the new row use VALUES, specifying the value you want for each column:
VALUES(col1,col2,col3,col4,col5)
*/


DROP TABLE IF EXISTS temp.new_vendor;
CREATE TABLE temp.new_vendor AS
SELECT vendor_id,
vendor_name,
vendor_type,
vendor_owner_first_name,
vendor_owner_last_name
FROM vendor;

INSERT INTO temp.new_vendor
(vendor_id, vendor_name, vendor_type, vendor_owner_first_name, vendor_owner_last_name)
VALUES
(10, 'Thomass Superfood Store', 'Fresh Focused', 'Thomas', 'Rosenthal')

-- Date
/*1. Get the customer_id, month, and year (in separate columns) of every purchase in the customer_purchases table.
Expand All @@ -93,4 +155,3 @@ Remember that money spent is quantity*cost_to_customer_per_qty.

HINTS: you will need to AGGREGATE, GROUP BY, and filter...
but remember, STRFTIME returns a STRING for your WHERE statement!! */