assignment 1 complete

02_activities/assignments/Cohort_8/assignment1.sql

@@ -2,31 +2,62 @@
 /* SECTION 2 */
 
 
---SELECT
+
 /* 1. Write a query that returns everything in the customer table. */
+select * from customer
 
 
 
 /* 2. Write a query that displays all of the columns and 10 rows from the cus- tomer table, 
-sorted by customer_last_name, then customer_first_ name. */
+sorted by customer_last_name, then customer_first_ name. */ 
+select * from customer
+order by customer_last_name,customer_first_name
+limit 10
+
 
 
 
 --WHERE
 /* 1. Write a query that returns all customer purchases of product IDs 4 and 9. */
 
-
+select product_id,
+vendor_id,
+market_date,
+customer_id,
+quantity,
+cost_to_customer_per_qty,
+transaction_time
+ from customer_purchases
+where product_id in ('4','9')
 
 /*2. Write a query that returns all customer purchases and a new calculated column 'price' (quantity * cost_to_customer_per_qty), 
 filtered by customer IDs between 8 and 10 (inclusive) using either:
 	1.  two conditions using AND
 	2.  one condition using BETWEEN
 */
 -- option 1
-
+select product_id,
+vendor_id,
+market_date,
+customer_id,
+quantity,
+cost_to_customer_per_qty,
+transaction_time,
+(quantity * cost_to_customer_per_qty) as price
+ from customer_purchases
+where customer_id in ('8','10')
 
 -- option 2
-
+select product_id,
+vendor_id,
+market_date,
+customer_id,
+quantity,
+cost_to_customer_per_qty,
+transaction_time,
+(quantity * cost_to_customer_per_qty) as price
+ from customer_purchases
+where customer_id between  '8'and '10'
 
 
 --CASE
@@ -35,18 +66,32 @@ Using the product table, write a query that outputs the product_id and product_n
 columns and add a column called prod_qty_type_condensed that displays the word “unit” 
 if the product_qty_type is “unit,” and otherwise displays the word “bulk.” */
 
-
+select 
+product_id,
+product_name,
+case when product_qty_type='unit' then 'unit'
+else 'bulk' end as prod_qty_type_condensed
+ from product
 
 /* 2. We want to flag all of the different types of pepper products that are sold at the market. 
 add a column to the previous query called pepper_flag that outputs a 1 if the product_name 
 contains the word “pepper” (regardless of capitalization), and otherwise outputs 0. */
 
-
+ select 
+product_id,
+product_name,
+case when product_qty_type='unit' then 'unit'
+else 'bulk' end as prod_qty_type_condensed,
+case when product_name like '%Peppers%' then '1' 
+else '0' end as pepper_flag
+ from product
 
 --JOIN
 /* 1. Write a query that INNER JOINs the vendor table to the vendor_booth_assignments table on the 
 vendor_id field they both have in common, and sorts the result by vendor_name, then market_date. */
-
+ select market_date,v.* from vendor v
+ inner join vendor_booth_assignments vba on v.vendor_id=vba.vendor_id
+ order by vendor_name,market_date ASC
 
 
 
@@ -56,7 +101,12 @@ vendor_id field they both have in common, and sorts the result by vendor_name, t
 /* 1. Write a query that determines how many times each vendor has rented a booth 
 at the farmer’s market by counting the vendor booth assignments per vendor_id. */
 
-
+ select 
+ vendor_id,
+ count(booth_number) as count_of_rent
+ from vendor_booth_assignments
+ group by vendor_id
+ order by count_of_rent DESC
 
 /* 2. The Farmer’s Market Customer Appreciation Committee wants to give a bumper 
 sticker to everyone who has ever spent more than $2000 at the market. Write a query that generates a list 
@@ -65,6 +115,18 @@ of customers for them to give stickers to, sorted by last name, then first name.
 HINT: This query requires you to join two tables, use an aggregate function, and use the HAVING keyword. */
 
 
+ select 
+customer_first_name,
+customer_last_name,
+c.customer_id,
+(quantity * cost_to_customer_per_qty) as total
+ from customer c
+inner join customer_purchases cp on c.customer_id=cp.customer_id
+group by 
+ customer_first_name,
+customer_last_name,
+c.customer_id
+ having (quantity * cost_to_customer_per_qty) 	> '2000'
 
 --Temp Table
 /* 1. Insert the original vendor table into a temp.new_vendor and then add a 10th vendor: 
@@ -86,11 +148,43 @@ VALUES(col1,col2,col3,col4,col5)
 HINT: you might need to search for strfrtime modifers sqlite on the web to know what the modifers for month 
 and year are! */
 
-
+select 
+	distinct 
+	customer_id,
+	product_name,
+	strftime('%m', market_date) as mon,---- this did not produced the desired result hence the substring used
+	substr(market_date,6,2) as month,
+	substr(market_date,1,4) as year,
+	strftime('%Y', market_date) as year2
+	 from customer_purchases a
+	 inner join product b on a.product_id=b.product_id
 
 /* 2. Using the previous query as a base, determine how much money each customer spent in April 2022. 
-Remember that money spent is quantity*cost_to_customer_per_qty. 
-
+Remember that money spent is quantity*cost_to_customer_per_qty. */
+
+with base as (select 
+customer_first_name,
+customer_last_name,
+c.customer_id,
+substr(market_date,6,2) as mon,
+market_date,
+(quantity * cost_to_customer_per_qty) as total
+ from customer c
+inner join customer_purchases cp on c.customer_id=cp.customer_id
+group by 
+ customer_first_name,
+customer_last_name,
+market_date,
+c.customer_id)
+select customer_first_name,
+customer_last_name,
+customer_id,
+sum(total)
+ from base
+where strftime('%m', market_date)  ='04'
+group by customer_last_name,
+customer_id
 HINTS: you will need to AGGREGATE, GROUP BY, and filter...
 but remember, STRFTIME returns a STRING for your WHERE statement!! */
 
+