Completed Sql4

Problem1.sql

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+# Write your MySQL query statement below
+WITH CTE AS (
+    SELECT employee_id, experience, SUM(salary) OVER (PARTITION BY experience ORDER BY salary, employee_id) AS rsum FROM Candidates
+)
+
+SELECT 'Senior' AS experience, COUNT(employee_id) AS accepted_candidates 
+FROM CTE
+WHERE experience = 'Senior' AND rsum <= 70000
+UNION
+SELECT 'Junior' AS experience, COUNT(employee_id) AS accepted_candidates
+FROM CTE
+WHERE experience = 'Junior' AND rsum <= (SELECT 70000 - IFNULL(MAX(rsum), 0) FROM CTE WHERE experience = 'Senior' AND rsum <= 70000);

Problem2.sql

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+# Write your MySQL query statement below
+WITH CTE AS (
+    SELECT home_team_id AS r1, away_team_id AS r2, home_team_goals AS g1, away_team_goals AS g2
+    FROM Matches
+    UNION ALL
+    SELECT away_team_id AS r1, home_team_id AS r2, away_team_goals AS g1, home_team_goals AS g2
+    FROM Matches
+)
+
+SELECT t.team_name, COUNT(c.r1) AS matches_played, 
+SUM(
+    CASE
+        WHEN c.g1 > c.g2 THEN 3
+        WHEN c.g1 = c.g2 THEN 1
+        ELSE 0
+    END) AS points, SUM(c.g1) AS goal_for, SUM(c.g2) AS goal_against, SUM(c.g1) - SUM(c.g2) AS goal_diff
+FROM Teams t
+INNER JOIN CTE c
+ON t.team_id = c.r1
+GROUP BY c.r1
+ORDER BY points DESC, goal_diff DESC, team_name ASC;

Problem3.sql

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+# Write your MySQL query statement below
+SELECT name FROM SalesPerson WHERE sales_id NOT IN 
+(SELECT o.sales_id FROM Orders o
+LEFT JOIN Company c ON o.com_id = c.com_id
+WHERE c.name = 'RED');

Problem4.sql

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+# Write your MySQL query statement below
+SELECT id, COUNT(*) AS num
+FROM 
+(SELECT requester_id AS id FROM RequestAccepted
+UNION ALL
+SELECT accepter_id AS id FROM RequestAccepted) AS combined
+GROUP BY id
+ORDER BY num DESC
+LIMIT 1;