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vrom911
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vrom911
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That's neat work 👌🏼 Congrats on finishing Chapter 3 🥇
| { bookTitle :: String | ||
| , bookAutor :: String | ||
| , bookPages :: Int | ||
| , bookPrice :: Int |
| Create a simple enumeration for the meal types (e.g. breakfast). The one who | ||
| comes up with the most number of names wins the challenge. Use your creativity! | ||
| -} | ||
| data Meal = Breakfast | Frühstück | Brunch | Lunch | Dinner | Supper | Snack | OnlyWater |
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🧀 🍨 🧊
These are new! Would need to add Frühstück into my schedule 😄
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It's the second German breakfast 🥳
| , cityHouses :: [House] | ||
| } | ||
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| data Castle = None | OnlyCastle | CastleWithWalls |
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The task tells that the castle should have a name. In this case, it can be a String.
Sorry, if it wasn't clear before. 😞 We improved this task wording in the latest version to clarify this moment.
Could you guess, what functions would need patching in case of the type modifications? 🙂
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I had read: Optional castle with a name, sorry. I'll try
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No worries, it's our bad that the wording wasn't clear!
| buildWalls :: City -> City | ||
| buildWalls city = case cityCastle city of | ||
| OnlyCastle -> | ||
| if sum (map countPeople (cityHouses city)) >= 10 |
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Nice combination of the standard functions 👍🏼
| let damage = calculatePlayerDamage (playerAttack player2) (playerStrength player2) | ||
| defense = calculatePlayerDefense (playerArmor player1) (playerDexterity player1) | ||
| newHealth = calculatePlayerHit damage defense (playerHealth player1) | ||
| in player1 { playerHealth = newHealth } |
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Nice work on newtypes! 🏅 Newtypes are one very important feature in Haskell 👍
| | otherwise = succ weekday | ||
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| daysToParty :: Weekday -> Int | ||
| daysToParty weekday = fromEnum Fri - fromEnum weekday |
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This would show the shortest distance to Friday, however, time doesn't work like this.
For example. if it is Saturday, it would tell you that it is -1 day to Friday, however, it is 6 days to go 🥳
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I changed the regular order of days because of this, but I am aware that this is a cheat 😰
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Yeah, this one way to do it, but I agree, that this looks like a cheat 😄
You can apply the knowledge that we know exactly that there are 7 days in a week. So we can just calculate everything by mod 7!
Let's look how it would work:
ghci> mod (5) 7
5
ghci> mod (-1) 7
6Looks like just what we need!
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Solutions for Chapter 3
cc @vrom911 @chshersh