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sadhanaa21
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May 17, 2023
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| mysql> select * from customer where RATING=100; |
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| 3) Find the largest order taken by each salesperson on each date. | ||
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| mysql> select s.SNAME, max(o.AMT) as orderAmount, ODATE from orders as o,salespeople as s where s.SNUM=o.SNUM group by o.SNUM,o.ODATE; |
| 8) Count the orders of each of the salespeople and output the results in descending order. | ||
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| mysql> SELECT s.snum, s.sname, COALESCE(COUNT(o.onum), 0) as order_count FROM salespeople as s LEFT JOIN orders as o ON s.snum = o.snum GROUP BY s.snum, s.sname ORDER BY order_count DESC; |
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SQL indentation required in all queries.
Module3/SQL_Assignment.txt
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| 21) List all the largest orders for October 3, for each salesperson. | ||
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| mysql> SELECT ONUM,ODATE,MAX(o.AMT) as AMOUNT from orders as o inner join salespeople as s on o.SNUM=s.SNUM where o.ODATE like '%-03-10' group by s.SNUM; |
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Left join should be used. Try to use appropriate joins in all queries as well.
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| 65) Write a query using ANY or ALL that will find all salespeople who have no customers located in their city. | ||
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Question clearly says you have to use ANY or ALL here.
| 7 rows in set (0.00 sec) | ||
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| 47) Write a query that lists each order number followed by the name of the customer who made that order. |
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Wrong data entered here. Correct it in all affected queries.
| | 1001 | Peel | London | 12 | 1990-03-10 | 9891.88 | | ||
| | 1002 | Serres | Sanjose | 13 | 1990-03-10 | 5160.45 | | ||
| | 1003 | AxelRod | New York | 10 | 1990-04-10 | 1713.23 | | ||
| +------+---------+-----------+------+------------+------------+ |
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Wrong dates in output corresponding to order amount
Module3/SQL_Assignment.txt
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| | Motika | 1990-03-10 | 3002 | 1900.1 | Rome | | ||
| | Rifkin | 1990-03-10 | 3006 | 1098.16 | Sanjose | | ||
| +---------+------------+------+---------+---------+ | ||
| 5 rows in set (0.00 sec) |
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Wrong output.
Also rework on query number 34, 71, 97, 107 as they are giving wrong outputs.
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I learned SQL in depth
-Learned basics of MYSQL/SQL
-Completed Module-3 all questions
-Learned in depth about SQL joins.