E

Alex Kerr labs/Alex Kerr Lab 2 guessing game.txt

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+import java.Math
+
+int num = math.Random(100) + 1;
+Print "guess a number between 100 and 1, what is your guess?";
+import user.guess;
+int n = 0;
+while (num != guess)
+{
+	if(num > guess)
+	{
+		print " your guess is too low, guess again ";
+		import new user.guess;
+		n++
+	}
+	else if(num < guess)
+	{
+		print " your guess is too high, guess again ";
+		import new user.guess;
+		n++
+	}
+	else if(num == guess)
+	{
+		Break;
+	}
+
+}
+if(num == guess)
+{
+	n++
+	Print "you guessed right! it took you " + n + " tries to guess the number correctly";
+}

Ben Wortman/BW Lab-2.java

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+
+
+
+
+public class Problem2{
+
+	 int num = 1579;												//starting number
+		System.out.println("The number is " + num);					//says the starting number
+
+	 for(i=0; number>1; i++)										//add one per loop
+
+	{if  (num % 2==0)												//if the number is divisible by 2 is a whole number
+		{ num = num/2;												//then divide the number by 2
+		System.out.println("The current number is " +num);}			//prints number after divided by 2
+
+	 else {num = num*3+1;											//if not divisible by 2 multiply by 3 and add 1
+
+		System.out.println("The current number is " +num)}}			//prints the number after multiplied by 3 and one added
+
+		System.out.println("There were" +i " operations")}			//prints how many times was a number sent through before it was 1
+
+
+
+
+
+

Jack Hinze/Lab 2.txt

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+3n+1 Problem
+Your program will be given a positive number (less than 10,000). Your program will take the number and follow the appropriate step below:
+
+when n is even, divide n by 2
+when n is odd, multiply n by 3, and then add 1
+When n is equal to one you stop, otherwise you pick the appropriate step again.
+
+Please print out the sequence of numbers that lead to 1, starting with n, and how many times (in sumation) the above two commands are run.
+
+Integer n = input number;
+step=0
+While (n > 1){
+		if (n%2==0){
+		n = n/2;
+		system.out.print(n);
+		step +=1
+		}
+		else{
+		n = 3*n + 1;
+		system.out.print(n);
+		step +=1;
+		}
+}
+system.out.print("# of steps:" step)

Jackson_Maschman_Question_2

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+public class Lab2 {
+    public static void main(String[] args)
+    {
+        //This is problem #2.
+        for(int n = 1; n < 10000; n++) //The parameters you set were numbers from 0 to less than 10000, so... here you go.
+        {
+            int counter = 0; //This sets the counter to 0 each time it finishes with one of the numbers.
+            while(n != 1) //This checks the number each loop to see if it has reached 1 yet.
+            {
+                if (n % 2 == 0) //This organizes the even numbers into this category.
+                {
+                        n = (n / 2);
+                        counter = counter + 1;
+                }
+
+                else { /* This organizes the odd numbers into this category. */
+                    n = ((n * 3) + 1);
+                    counter = counter + 1;
+                }
+
+            }
+            System.out.println(n + " It took " + counter + " loops to complete.");
+        }
+    }
+}

Jared Pohlmann/3n + 1 Problem

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+Integer num = input number;
+step=0
+While (num > 1){
+	if (num%2==0){
+	num= num/2;
+	system.out.print(num);
+	step += 1;
+	}
+	else{
+	num = num*3 +1;
+	system.out.print(num);
+	step += 1;
+	}
+}
+system.out.print("# of steps:" step)

Kristen Benes/Lab 2.txt

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+Lab 2
+Problem 2
+Your program will be given a positive number (less than 10,000). Your program will take the number and follow the appropriate step below:
+	When n is even, divide n by 2
+	when n is odd, multiply n by 3, and then add 1
+When n is equal to one you stop, otherwise you pick the appropriate step again.
+Please print out the sequence of number that lead to 1, starting with n, and how many times (in sumation) the above two commands are run.
+~~~~~~~~~~~~~~~~~~~~~~~~~~~~~~~~~~~~~~~~~~~~~~~~~~~~~~~~~~~~~~~~~~~~~~~~~~~~~~~~~~~~~~~~~~~~~~~~~~~~~~~~~~~~~~~~~~~~~~~~~~~~~~~~~~~~~~~~~
+n = input number;
+step = 0
+While (n > 1){
+	If (n%2==0){
+	n = (n/2);
+	system.out.print(n);
+	step +=1;
+	}
+	Else{
+	n = n*3+1;
+	system.out.print(n);
+	step +=1;
+	}
+}
+system.out.print("# of steps:" step)

addyvinton/addyvintonlab2.txt

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+n = number
+
+for (
+if(n%2 == 0)
+{
+
+n = n/2
+
+}
+
+else
+{
+
+n = (n*3) + 1
+
+}

bkeller lab2

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+PROBLEM 3
+
+
+
+n = getRandomNumber(0:100);
+u = user input;
+"guess" = 1
+If (n > u){
+    system.out.print(n);
+    "LOW";
+   "guess"+=1;
+   }
+If (n < u){
+    system.out.print(n);
+    "HIGH";
+    "guess"+=1;
+    }
+If (n == u)
+    system.out.print(n);
+    "CORRECT";
+    }
+}
+system.out.print("number of "guesses:" guesses)

piiamt/2n+1 problem.txt

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+public class Problem2{
+	int number = 56;							//this is the number given to the program
+	System.out.println("The inserted number is " + number);			//prints the number given to the program
+	for (i=0; number>1; i++){ 						//every loop the counter i will be increased by one, that is the total number of operations. continues as long as number is bigger than 1
+		if (number%2 != 0){ 						//if number/2 does not have a remainder (number is divisible by 2) then
+			number=number/2;  					//the number will be redefined as the number itself divided by 2
+			System.out.println("The current number is "+number);	//prints the number after dividing it by 2
+		}
+		else { 								//when the condition of the if statement does not apply (number is not even) then executes this part that
+			number=number*3+1;					//multiplies the number by 3 and adds 1, redefines number to it.
+			System.out.println("The current number is "+number);
+		}
+	System.out.println("The total number of operations was "+i)		//prints out the number of operations
+}

skylar galloway lab/Lab2 3n+1 problem.txt

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+3n+1
+
+The 3n + 1 problem
+Your program will be given a positive number (less than 10,000). Your program will take the number and follow the appropriate step below:
+
+when n is even, divide n by 2
+when n is odd, multiply n by 3, and then add 1
+When n is equal to one you stop, otherwise you pick the appropriate step again.
+
+Please print out the sequence of numbers that lead to 1, starting with n, and how many times (in sumation) the above two commands are run.
+
+n = input number
+int counter=0 /*the value that keeps track of how many times number runs through the loop*/
+
+for(int i=0, n!=1 /*(this is tested before loop is executed)*/, i++){
+	if (n%2==0){
+		w=n/2        //can be n=n/2
+		Print w
+		count= counter +1
+		counter=count
+		n=w
+	}
+	else { // (n%2!=0)
+		x=3*n
+		y=x+1
+		coUnt= counter +1
+		counter=coUnt
+		Print y
+		n=y
+	}
+}
+Print n
+Print "The number of times ran throught"+counter
+
+

ylopez20/Lab2.md

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+//Problem 2
+~~~
+n = input number
+for(n=1, n<1000)
+{
+    n counter = 0;
+    while(n!=1)
+    {
+      if(n%2==0)
+      ncounter= n+1;
+    }
+
+    else
+    n=n*3+1;
+    ncounter =n+1
+ }
+ ~~~