recitation E code: pig latin exercise, no errors

E-Memory-Pointers/code/pig_latin.c

@@ -0,0 +1,104 @@
+#include <stdio.h>
+#include <string.h>
+#include <stdlib.h>
+
+char *convert(char *word, char *pig_word) {
+
+	/*
+	 * Copy second half of word to first half of pig_word
+	 *
+	 */
+
+	int half_word_len = strlen(word)/2;
+
+	strcpy(pig_word, word + half_word_len);
+
+	/*
+	 * Copy first half of word to second half of pig_word
+	 *
+	 */	
+
+
+	int idx = 0;
+	int start_idx = strlen(pig_word);
+
+	while(idx < half_word_len) {
+
+		pig_word[start_idx + idx] = *(word + idx);
+		idx++;
+	}
+
+
+	pig_word[start_idx + idx] = 0;
+
+	/*
+	 * Append "ay" to end of pig_word
+	 *
+	 */
+
+	strcat(pig_word, "ay");
+
+	return pig_word;
+}
+
+int main(int argc, char **argv) {
+
+	/*
+	 * Allocate space and evaluate phrase_len using sizeof()
+	 *
+	 */
+
+	char *pig_phrase[argc];
+	pig_phrase[argc - 1] = NULL;
+
+	int phrase_len = sizeof(pig_phrase) / sizeof(char *);
+
+
+        /*
+	 * iterate through phrase 
+	 * we will allocate space for each word
+	 * then pass that space to be filled by a convert function	
+	 *
+	 */	
+
+	for (int i = 1; i < argc; i++) {
+
+		char *word = *(argv+i);
+
+		/*
+		 * Allocate space for new word 
+		 *
+		 */
+
+		int pig_word_len = strlen(word) + strlen("ay") + 1;
+
+
+		// Program wont work unless we malloc, reveal later 
+		//char pig_word[pig_word_len];
+		char *pig_word = malloc(pig_word_len * sizeof(char));
+
+		/*
+		 * Fill in array with converted pointer
+		 *
+		 */		
+
+		pig_phrase[i-1] = convert(word, pig_word);	
+
+	}
+
+	/* 
+	 * Iterate through and print new phrase
+	 *
+	 */
+	char **pig_phrase_itr = pig_phrase;
+	/*
+	 * Question: Why do we need a char** here instead of using pig_phrase itself?
+	 *
+	 */
+	while (*pig_phrase_itr){
+		printf("%s ", *pig_phrase_itr);
+		free(*pig_phrase_itr);
+		pig_phrase_itr++;
+	}
+	printf("\n");
+}