diff --git a/02_activities/assignments/Cohort_8/Assignment_One_Chude.drawio.png b/02_activities/assignments/Cohort_8/Assignment_One_Chude.drawio.png new file mode 100644 index 000000000..6cf352344 Binary files /dev/null and b/02_activities/assignments/Cohort_8/Assignment_One_Chude.drawio.png differ diff --git a/02_activities/assignments/Cohort_8/assignment1.sql b/02_activities/assignments/Cohort_8/assignment1.sql index c992e3205..ec76662cf 100644 --- a/02_activities/assignments/Cohort_8/assignment1.sql +++ b/02_activities/assignments/Cohort_8/assignment1.sql @@ -2,20 +2,33 @@ /* SECTION 2 */ ---SELECT + /* 1. Write a query that returns everything in the customer table. */ +select * from customer /* 2. Write a query that displays all of the columns and 10 rows from the cus- tomer table, -sorted by customer_last_name, then customer_first_ name. */ +sorted by customer_last_name, then customer_first_ name. */ +select * from customer +order by customer_last_name,customer_first_name +limit 10 + --WHERE /* 1. Write a query that returns all customer purchases of product IDs 4 and 9. */ - +select product_id, +vendor_id, +market_date, +customer_id, +quantity, +cost_to_customer_per_qty, +transaction_time + from customer_purchases +where product_id in ('4','9') /*2. Write a query that returns all customer purchases and a new calculated column 'price' (quantity * cost_to_customer_per_qty), filtered by customer IDs between 8 and 10 (inclusive) using either: @@ -23,10 +36,28 @@ filtered by customer IDs between 8 and 10 (inclusive) using either: 2. one condition using BETWEEN */ -- option 1 - +select product_id, +vendor_id, +market_date, +customer_id, +quantity, +cost_to_customer_per_qty, +transaction_time, +(quantity * cost_to_customer_per_qty) as price + from customer_purchases +where customer_id in ('8','10') -- option 2 - +select product_id, +vendor_id, +market_date, +customer_id, +quantity, +cost_to_customer_per_qty, +transaction_time, +(quantity * cost_to_customer_per_qty) as price + from customer_purchases +where customer_id between '8'and '10' --CASE @@ -35,18 +66,32 @@ Using the product table, write a query that outputs the product_id and product_n columns and add a column called prod_qty_type_condensed that displays the word “unit” if the product_qty_type is “unit,” and otherwise displays the word “bulk.” */ - +select +product_id, +product_name, +case when product_qty_type='unit' then 'unit' +else 'bulk' end as prod_qty_type_condensed + from product /* 2. We want to flag all of the different types of pepper products that are sold at the market. add a column to the previous query called pepper_flag that outputs a 1 if the product_name contains the word “pepper” (regardless of capitalization), and otherwise outputs 0. */ - + select +product_id, +product_name, +case when product_qty_type='unit' then 'unit' +else 'bulk' end as prod_qty_type_condensed, +case when product_name like '%Peppers%' then '1' +else '0' end as pepper_flag + from product --JOIN /* 1. Write a query that INNER JOINs the vendor table to the vendor_booth_assignments table on the vendor_id field they both have in common, and sorts the result by vendor_name, then market_date. */ - + select market_date,v.* from vendor v + inner join vendor_booth_assignments vba on v.vendor_id=vba.vendor_id + order by vendor_name,market_date ASC @@ -56,7 +101,12 @@ vendor_id field they both have in common, and sorts the result by vendor_name, t /* 1. Write a query that determines how many times each vendor has rented a booth at the farmer’s market by counting the vendor booth assignments per vendor_id. */ - + select + vendor_id, + count(booth_number) as count_of_rent + from vendor_booth_assignments + group by vendor_id + order by count_of_rent DESC /* 2. The Farmer’s Market Customer Appreciation Committee wants to give a bumper sticker to everyone who has ever spent more than $2000 at the market. Write a query that generates a list @@ -65,6 +115,18 @@ of customers for them to give stickers to, sorted by last name, then first name. HINT: This query requires you to join two tables, use an aggregate function, and use the HAVING keyword. */ + select +customer_first_name, +customer_last_name, +c.customer_id, +(quantity * cost_to_customer_per_qty) as total + from customer c +inner join customer_purchases cp on c.customer_id=cp.customer_id +group by + customer_first_name, +customer_last_name, +c.customer_id + having (quantity * cost_to_customer_per_qty) > '2000' --Temp Table /* 1. Insert the original vendor table into a temp.new_vendor and then add a 10th vendor: @@ -86,11 +148,43 @@ VALUES(col1,col2,col3,col4,col5) HINT: you might need to search for strfrtime modifers sqlite on the web to know what the modifers for month and year are! */ - +select + distinct + customer_id, + product_name, + strftime('%m', market_date) as mon,---- this did not produced the desired result hence the substring used + substr(market_date,6,2) as month, + substr(market_date,1,4) as year, + strftime('%Y', market_date) as year2 + from customer_purchases a + inner join product b on a.product_id=b.product_id /* 2. Using the previous query as a base, determine how much money each customer spent in April 2022. -Remember that money spent is quantity*cost_to_customer_per_qty. - +Remember that money spent is quantity*cost_to_customer_per_qty. */ + +with base as (select +customer_first_name, +customer_last_name, +c.customer_id, +substr(market_date,6,2) as mon, +market_date, +(quantity * cost_to_customer_per_qty) as total + from customer c +inner join customer_purchases cp on c.customer_id=cp.customer_id +group by + customer_first_name, +customer_last_name, +market_date, +c.customer_id) +select customer_first_name, +customer_last_name, +customer_id, +sum(total) + from base +where strftime('%m', market_date) ='04' +group by customer_last_name, +customer_id HINTS: you will need to AGGREGATE, GROUP BY, and filter... but remember, STRFTIME returns a STRING for your WHERE statement!! */ +