From b8a5cb1cdc9793d4283b72e2b4e9cf5cc0cac032 Mon Sep 17 00:00:00 2001
From: Haswatha Sridharan <haswathas@gmail.com>
Date: Tue, 17 Jun 2025 19:11:20 -0500
Subject: [PATCH] Sql4 Completed

---
 README.md | 56 +++++++++++++++++++++++++++++++++++++++++++++++++++++++
 1 file changed, 56 insertions(+)

diff --git a/README.md b/README.md
index 1c9b489..baeb6ed 100644
--- a/README.md
+++ b/README.md
@@ -2,8 +2,64 @@
 
 1 Problem 1 : The Number of Seniors and Juniors to Join the Company	(https://leetcode.com/problems/the-number-of-seniors-and-juniors-to-join-the-company/)
 
+Solution:
+WITH CTE AS(
+SELECT employee_id , experience , SUM(salary) OVER(PARTITION BY experience ORDER BY salary ,employee_id)
+ as 'rsum'FROM candidates)
+
+ SELECT 'Senior' AS experience , COUNT(employee_id) AS 'accepted_candidates' FROM CTE WHERE experience = 'Senior'
+ AND rsum <=70000
+ UNION
+ SELECT 'Junior' AS experience , COUNT(employee_id) AS 'accepted_candidates' FROM CTE WHERE experience = 'Junior'
+ AND rsum <= (SELECT 70000 - IFNULL(MAX(rsum),0) from CTE where experience = 'Senior' AND rsum <= 70000);
+
+
 2 Problem 2 : League Statistics		(https://leetcode.com/problems/league-statistics/ )
 
+Solution:
+WITH CTE AS(
+SELECT home_team_id as r1 , away_team_id as r2 , home_team_goals as g1 , away_team_goals as g2 from matches
+UNION ALL
+Select away_team_id as r1 , home_team_id as r2 , away_team_goals as g1 , home_team_goals as g2 from matches
+)
+
+SELECT t.team_name , COUNT(c.r1) as 'matches_played' , SUM(
+    CASE
+        WHEN c.g1 > c.g2 THEN 3
+        WHEN c.g1 = c.g2 THEN 1
+        ELSE 0
+    END
+)AS 'points' , SUM(c.g1) AS 'goal_for',SUM(c.g2) AS 'goal_against',SUM(c.g1) - SUM(c.g2) AS 'goal_diff'
+FROM teams t JOIN CTE c ON t.team_id = c.r1 GROUP BY c.r1 ORDER BY points DESC , goal_diff DESC ,
+t.team_name;
+
+
 3 Problem 3 : Sales Person		(https://leetcode.com/problems/sales-person/ )
 
+Solution:
+SELECT S.name 
+from SalesPerson S
+Where sales_id Not in (
+    select o.sales_id 
+    from orders o
+    join company c
+    on o.com_id = c.com_id
+    where c.name = 'RED'
+)
+
 4 Problem 4 : Friend Requests II	(https://leetcode.com/problems/friend-requests-ii-who-has-the-most-friends/ )
+
+Solution:
+WITH CTE AS(
+    SELECT requester_id as r1 from RequestAccepted
+    UNION ALL
+    SELECT accepter_id as r1 from RequestAccepted
+),
+
+ACTE AS(
+SELECT r1 as 'id' , COUNT(r1) AS 'num' from CTE GROUP BY r1
+)
+
+SELECT id , num FROM ACTE WHERE num = (SELECt MAX(num) from ACTE) LIMIT 1;
+
+