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New test #17

@hyfi06

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@hyfi06

Los test se pueden pasar usando dos niveles de iteración, ya que los test actuales son resultados sólo tienen 2 números diferentes.

Sugiero añadir el siguiente test:

expect(combinationSum(combinationSum([2, 3, 5, 7], 17))).toEqual([
  [2, 2, 2, 2, 2, 2, 2, 3],
  [2, 2, 2, 2, 2, 2, 5],
  [2, 2, 2, 2, 2, 7],
  [2, 2, 2, 2, 3, 3, 3],
  [2, 2, 2, 3, 3, 5],
  [2, 2, 3, 3, 7],
  [2, 2, 3, 5, 5],
  [2, 3, 3, 3, 3, 3],
  [2, 3, 5, 7],
  [2, 5, 5, 5],
  [3, 3, 3, 3, 5],
  [3, 7, 7],
  [5, 5, 7]
]);

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